| (8.40) |
The filter W(y)=1/Y for
and 0 otherwise, for example, gives a running average of the values extending
backward for an interval Y. While such a filter does not change
the mean value of a stationary process, the autocovariance and spectral
density will change.
The autocovariance function in terms of the filtered variables becomes
| (8.41) |
The variance spectrum in terms of the filtered time series is then
| (8.42) |
or the original variance spectrum multiplied by the squared magnitude of the Fourier transform of the weighting functions.
In the case of a running average, calculation of the Fourier transform of the filter function gives
| (8.43) |
The filter reduces frequencies higher than 1/T, but it does not have a sharp cutoff and it distorts the spectrum at frequencies below 1/T, so this is usually a poor choice for a filter.