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8.6 Relationship of autocovariance function to variance spectrum

The following derivation shows that the variance spectrum and the autocovariance function are Fourier transforms of each other:
 
$\displaystyle {rl}\Gamma(\nu)$ $\textstyle = {\rm lim}_{T\rightarrow\infty}\vert c_k\vert^2 T, \ \ (\nu =k/T)$    
  $\textstyle = {\rm lim}_{T\rightarrow\infty}\Bigl\{T\bigl({{1}\over{T}}\int_{-T......\int_{-T/2}^{T/2}f^\prime(t^\prime)e^{-i2\pi\nut^\prime}dt^\prime\bigr)\Bigr\}$   (8.26)
 
where $f^\prime(t)=f(t)-\overline{f(t)}$ is the time series with mean subtracted from all values. If the integration variable is changed from t to $\tau=t-t^\prime$, so that $t=t^\prime+\tau$ and $-T\le\tau\le T$, then
$\displaystyle {rl}\Gamma(\nu)$ $\textstyle = {\rm lim}_{T\rightarrow\infty} \int_{-T}^T\Bigl[{{1}\over{T}}\int......f^\prime(t^\prime+\tau)f^\prime(t^\prime)dt^\prime\Bigr]e^{-i2\pi\nu\tau}d\tau$    
  $\textstyle = \int_{-\infty}^{\infty}V_{ff}(\tau)e^{-i2\pi\nu\tau}d\tau \ \ .$   (8.27)
 
This shows that the variance spectrum is the Fourier transform of the autocovariance function, and similarly the autocovariance function is the Fourier transform of the variance spectrum:
\begin{displaymath}V_{ff}(\tau) = \int_{-\infty}^\infty\Gamma(\nu)e^{i2\pi\nu\tau}d\nu . \end{displaymath} (8.28)
 

Note that the total variance is

\begin{displaymath}\sigma^2 = V_{ff}(0) = \int_{-\infty}^\infty\Gamma(\nu)d\nu .\end{displaymath} (8.29)
 
 


Exercise 8.1: Suppose that the variance spectrum for the vertical wind is given by
\begin{displaymath}\Gamma(\nu) = 0.67 {{2\pi}\over{V}}^{-2/3} \epsilon^{2/3} \nu^{-5/3} \end{displaymath} (8.30)
 

as is expected for observations made in an "inertial subrange" from an aircraft flying at airspeed V. (Here $\epsilon$ characterizes the eddy dissipation rate, and has units of (energy)(mass)-1(time)-1.) Find the expected functional form of the autocorrelation function.



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