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4.2.1 Weighted averages

If measurements $\{x\}$ are taken from a population with a Gaussian distribution, but are made with varying measurement uncertainties $\{\sigma\}$, what is the best estimate of the sample mean? The likelihood function for this case is
\begin{displaymath}{\cal L}(a) = \prod_i {{1}\over{\sigma_i\sqrt{2\pi}}} \exp\{-{{(x_i-a)^2}\over{2\sigma_i^2}}\} \end{displaymath} (4.12)
 

and

\begin{displaymath}W(a) = -\sum_i {{(x_i-a)^2}\over{2\sigma_i^2}} + {\rm constant}. \end{displaymath} (4.13)
 

The maximum occurs for

\begin{displaymath}{{\partial W(a)}\over{\partial a}}\Bigr\vert _{a^*} = \sum_i ......{x_i}\over{\sigma_i^2}}) -\sum_i {{a^*}\over{\sigma_i^2}} = 0 \end{displaymath} (4.14)
 

or

\begin{displaymath}a^* = {{\sum_i(x_i /\sigma_i^2)}\over{\sum_i(1 /\sigma_i^2)}} .\end{displaymath} (4.15)
 

This is a weighted average of the measurements, with weight factors inversely proportional to the square of the uncertainty.

Because

\begin{displaymath}{{\partial^2W}\over{\partial a^2}}\Bigr\vert _{a^*} = -\sum_i{{1}\over{\sigma_i^2}} , \end{displaymath} (4.16)
 

the estimated uncertainty in the weighted average, from (4.11), is

\begin{displaymath}\sigma_{a^*} = \bigl[\sum_i {{1}\over{\sigma_i^2}}\bigr]^{-1/2} .\end{displaymath} (4.17)
  


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